@studnicky/v8/with-statement

Disallows every with statement. A with statement changes name resolution for its body at runtime, so the engine cannot rely on the lexical binding for an unqualified name and optimization is impaired. TypeScript strict-mode code also rejects this legacy JavaScript construct.

Fixable: No · Options: No · Suggested severity: error

✗ Incorrect

with (Math) {
  const radius = sqrt(pow(x, 2) + pow(y, 2));
}

✓ Correct

const radius = Math.sqrt(Math.pow(x, 2) + Math.pow(y, 2));

const { pow, sqrt } = Math;
const radius = sqrt(pow(x, 2) + pow(y, 2));